20x-x^2=160

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Solution for 20x-x^2=160 equation: 



20x-x^2=160

We move all terms to the left:

20x-x^2-(160)=0

We add all the numbers together, and all the variables

-1x^2+20x-160=0

a = -1; b = 20; c = -160;
Δ = b2-4ac
Δ = 202-4·(-1)·(-160)
Δ = -240
Delta is less than zero, so there is no solution for the equation

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